Gears

Gears transmit motion and torque with a fixed ratio. Learn spur, helical, bevel and worm gears, module and pitch geometry, gear ratios and trains, tooth forces, Lewis bending and AGMA/ISO contact stress, and gear materials.

From wristwatches to wind turbines, gears change speed and torque precisely and efficiently (up to 99 % per mesh). A small pinion driving a large gear reduces speed and multiplies torque.

Designers choose tooth size (module), tooth counts, face width and material so the teeth survive bending fatigue and surface pitting for the required life.

An analogy

Bicycle chainrings and sprockets: a small front ring with a big rear sprocket makes climbing easy (more torque, less speed) — gears do the same without a chain.

Gear types

Spur: straight teeth, parallel shafts, simple, noisy at speed. Helical: angled teeth, smoother and quieter, create axial thrust. Bevel: intersecting shafts (differentials). Worm: high ratios (10–100:1) at right angles, can be self-locking but less efficient. Planetary: compact high ratios with torque split among planets.

Involute teeth and module

Involute tooth profiles keep the speed ratio constant even if centre distance varies slightly. Mating gears must share module and pressure angle. Fewer than ~17 teeth (20°) causes undercutting unless profile-shifted.

Gear trains

Compound train ratio = product of individual ratios. Planetary sets: with sun input and ring fixed, i = 1 + z_ring/z_sun. Each mesh loses ~1–2 % (spur/helical); worms lose much more.

Rating: bending and pitting

Teeth fail by root bending fatigue (Lewis/AGMA J-factor) and surface pitting from Hertzian contact stress (σ_H ∝ √(F_t/(b d))). ISO 6336/AGMA 2001 apply factors for dynamic load, load distribution, size, reliability and life. Case-hardened (carburised) steel gears, ground teeth, profile/lead modifications and good lubrication maximise capacity and minimise noise — critical in EV gearboxes.

Formulas

Worked example: Gear geometry and forces

Given: Pinion z = 20, gear z = 60, m = 3 mm, φ = 20°; 10 kW at 1440 rpm on the pinion

Find: Diameters, centre distance, forces.

Answer: a = 120 mm; F_t ≈ 2.21 kN, F_r ≈ 0.80 kN

Worked example: Lewis bending check

Given: F_t = 2210 N, b = 30 mm, m = 3; Y = 0.32 (20 teeth)

Find: Root bending stress.

Answer: ≈ 77 MPa — acceptable for through-hardened steel

Common mistakes

Applications

Key takeaways

Going further