Wind

Wind turbines convert the kinetic energy of moving air into electricity. Learn the power equation and v³ law, the Betz limit, tip-speed ratio, power curves, wind shear, capacity factor and generator/converter types.

A wind turbine's rotor slows the air passing through it and extracts part of its kinetic energy. Modern turbines have 3 blades up to 120 m long, hubs over 150 m high, and ratings from 3 MW onshore to 15+ MW offshore.

Because power rises with the cube of wind speed, a site's wind resource dominates its economics — small differences in average speed mean large differences in energy.

An analogy

A wind turbine is like a sail that spins instead of pulling: double the wind speed and you get eight times the push-power, which is why a slightly windier hill is worth so much more.

The cube law

Power in the wind is ½ρAv³. Doubling wind speed gives 8× the power; a site averaging 7.5 m/s offers ~95 % more power than one at 6 m/s. Doubling rotor diameter gives 4× the area and 4× the power.

Betz limit and C_p

A turbine can't stop the air completely (it would pile up), so at most 16/27 ≈ 59.3 % of the wind's power can be extracted. Modern turbines reach C_p ≈ 0.45–0.50 at their optimal tip-speed ratio (λ ≈ 7–9 for three-bladed rotors).

Power curve and control

Below cut-in (~3 m/s) nothing is generated; between cut-in and rated speed (~11–13 m/s), variable-speed control keeps λ optimal for maximum C_p; above rated speed, blade pitch control spills excess power to hold rated output; above cut-out (~25 m/s) the turbine feathers and stops for safety.

Generators and grid connection

Type 3 turbines use doubly-fed induction generators with a partial-rated converter on the rotor; Type 4 use full-converter PMSG or induction generators, fully decoupling rotor speed from grid frequency and providing strong grid-support functions. Offshore farms connect via HVAC or HVDC export cables.

Resource assessment

Wind speeds follow a Weibull distribution; annual energy = ∫ power curve × probability. Wake losses inside farms, turbulence, air density at altitude and availability all feed the P50/P90 energy estimates that finance projects.

Formulas

Worked example: Power of a 100 m rotor

Given: D = 100 m → A = π × 50² = 7854 m²; v = 10 m/s, ρ = 1.225; C_p = 0.45

Find: Electrical power (ignoring drivetrain losses).

Answer: ≈ 2.2 MW

Worked example: Effect of hub height

Given: v = 5 m/s at 10 m; Hub at 100 m, α = 0.14

Find: Hub-height speed and power gain.

Answer: 6.9 m/s → 2.6× more power

Common mistakes

Applications

Key takeaways

Going further