DIAC

The DIAC is a symmetrical breakover device that fires a sharp pulse when its voltage reaches ~30 V. Learn its I–V characteristic, negative resistance, and how RC–DIAC networks set a TRIAC's firing angle in classic dimmers.

A DIAC is a two-terminal device that blocks until the voltage across it reaches its breakover voltage (typically 28–36 V) in either polarity, then snaps into conduction with a drop of several volts. That snap dumps a capacitor's charge into a TRIAC's gate as a clean, fast trigger pulse.

The classic analogue dimmer — potentiometer, capacitor, DIAC, TRIAC — is still built by the million because it needs no microcontroller.

An analogy

A DIAC is like a pressure-relief valve that stays shut until the pressure reaches a set point, then opens fully and suddenly, releasing a burst.

Symmetric breakover

Below V_BO only a tiny leakage current flows. At ±V_BO the DIAC avalanches and its voltage falls back by ΔV while current rises — a negative-resistance region. It behaves identically for both polarities, so one DIAC triggers both half-cycles of a TRIAC.

RC phase-shift trigger

A potentiometer and capacitor form a phase-shifting network across the supply. The capacitor voltage lags the supply by φ = arctan(ωRC) and is smaller in amplitude. When it reaches V_BO the DIAC fires, discharging the capacitor into the TRIAC gate. Larger R → more lag and a smaller amplitude → later firing → lower power.

Hysteresis ('snap-on') and double time constants

After the DIAC fires, the capacitor voltage drops, so the next half-cycle starts from a different initial condition: turning the pot up from 'off', the lamp snaps on at a mid brightness. Adding a second RC stage and a resistor reduces this hysteresis and extends the control range.

Replacing DIACs

MCU-based dimmers replace the RC–DIAC network with zero-cross detection and timed gate pulses, enabling remote control and LED compatibility. Silicon bilateral switches (SBS) offer lower, more precise breakover voltages when accuracy matters.

Formulas

Worked example: Firing angle at R = 100 kΩ

Given: V = 230 V RMS, 50 Hz; R = 100 kΩ, C = 100 nF; V_BO = 32 V

Find: Capacitor voltage, phase lag and firing angle.

Answer: α ≈ 91° → about half power

Worked example: Trigger pulse energy

Given: C = 100 nF; Fold-back ΔV = 10 V

Find: Charge delivered to the gate.

Answer: ≈ 1 µC, ~200 mA pulse

Common mistakes

Applications

Key takeaways

Going further