Structural Analysis

Structural analysis finds internal forces and deflections in beams, frames and trusses. Learn determinate vs indeterminate structures, continuous beams, fixed-end moments, moment distribution, slope-deflection, the stiffness (matrix) method and influence lines.

Most real structures — continuous beams, rigid frames, multi-storey buildings — have more supports and connections than equilibrium alone can resolve. They are statically indeterminate, and their internal forces depend on stiffness as well as loads.

Structural analysis combines equilibrium, compatibility (how parts deform together) and material behaviour to find bending moments, shears, axial forces and deflections everywhere — the input to every design check.

An analogy

Several people carrying a long plank share the load according to how firmly each holds it: a stiffer support attracts more load. Indeterminate structures share load by stiffness.

Why indeterminate?

Extra supports and rigid joints make structures stiffer, reduce peak moments and give redundancy — if one member is damaged, loads find another path. The price is that analysis needs compatibility equations or a computer.

Classical methods

Force (flexibility) method: remove redundants, compute deflections, restore compatibility. Slope-deflection: express member end moments in terms of joint rotations. Moment distribution (Hardy Cross): lock all joints, apply fixed-end moments, then release and distribute unbalanced moments by stiffness, carrying half over to far ends — iterate until balanced.

Influence lines

For moving loads (vehicles, cranes) an influence line shows how a reaction, shear or moment at one point varies as a unit load travels along the structure. Multiplying by axle loads (or integrating a UDL) gives the maximum effect and the critical load position.

Matrix stiffness method and software

Each member's stiffness matrix is assembled into [K]; solving [K]{d} = {F} gives joint displacements, then member forces. This is what STAAD.Pro, ETABS, SAP2000 and Robot do — plus P-Δ (second-order), nonlinear, dynamic and staged-construction analyses. Engineers must still check results with hand methods.

Formulas

Worked example: Two-span continuous beam

Given: Two equal spans L = 6 m; UDL w = 20 kN/m

Find: Reactions and moments.

Answer: R = 45/150/45 kN; M = −90 (support), +50.6 kN·m (span)

Worked example: Fixed-end moment

Given: Fixed-fixed beam L = 6 m, w = 20 kN/m

Find: End and mid-span moments.

Answer: −60 at ends, +30 kN·m at mid-span

Common mistakes

Applications

Key takeaways

Going further